5x^2-194x-240=0

Solution for 5x^2-194x-240=0 equation:

5x^2-194x-240=0

a = 5; b = -194; c = -240;
Δ = b2-4ac
Δ = -1942-4·5·(-240)
Δ = 42436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{42436}=206$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-194)-206}{2*5}=\frac{-12}{10}
=-1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-194)+206}{2*5}=\frac{400}{10}
=40
$